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Marina86 [1]
3 years ago
5

Ms. Lunette has 18 students in her class. She wants to send 3 of these students to pick up books for the class.

Mathematics
1 answer:
tigry1 [53]3 years ago
7 0

The number of possible combinations is given by

... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations

_____

There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.

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What is 9 to the power of 4 + 6(7 x 3) - 3?
marshall27 [118]

Answer: 127^9 so 8594754748609400000

Step-by-step explanation: i’m not sure but 4+6 (7x3)-3 = 127 127^9

5 0
3 years ago
A bottle of la belle bœuf contains 3/8 ounces of perfume. How many ounces of perfume would 4 1/2 bottles contain?
dusya [7]

ANSWER

1 \frac{11}{16} ounces

EXPLANATION

It was given that,a bottle of la belle bœuf contains 3/8 ounces of perfume.

We want to find how many ounces of perfume would 4 1/2 bottles contain.

If 1 bottle contains 3/8 ounces;

Then 4½ bottles should contain more ounces.

If more less divides.

4½ bottles contain

\frac{4 \frac{1}{2} \times  \frac{3}{8}  }{1}

=  \frac{27}{16}

=1.6875 ounces.

3 0
3 years ago
How many possible committees of 4 people can be chosen from 15 men and 20 women so that at least two women should be on each com
Mnenie [13.5K]

<span>If there has to be 2 men and 2 women, we know that we must take a group of 2 men out of the group of 15 men and a group of 2 women out of the group of 20 women. Therefore, we have:

(15 choose 2) x (20 choose 2)


(15 choose 2) = 105

(20 choose 2) = 190

190*105 = 19950

Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>

 

<span>If there has to be 1 man and 3 women, we know that we must take a group of 1 man out of the group of 15 men and a group of 3 women out of the group of 20 women. Therefore, we have:

(15 choose 1) x (20 choose 3)


(15 choose 1) = 15

(20 choose 3) = 1140

15*1140 = 17100

Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>

 

<span>We now find the total outcomes of having a group with 4 women.

We know this is the same as saying (20 choose 4) = 4845</span>

Therefore, there are 4845 ways to have a group of 4 with 4 women.

 

We now add the outcomes of 2 women, 3 women, and 4 women and get the total ways that a committee can have at least 2 women.

 

19950 + 17100 + 4845 = 41895 ways that there will be at least 2 women in the committee


5 0
3 years ago
Fine the distance between p(2,8 and q(5,3)
defon
d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}
d = \sqrt{(5 - 2)^{2} + (3 - 8)^{2}}\
d = \sqrt{(3)^{2} + (-5)^{2}}
d = \sqrt{9 + 25}
d = \sqrt{34}
7 0
3 years ago
If g = 77 cm and h = 85 cm, what is the length of f?
puteri [66]
<span>Your answer is: D. 115 cm</span>
3 0
3 years ago
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