A, B, and C are the coefficients. They are not the terms as you have written now.
A quadratic equation is in the form Ax^2 + Bx + C. Therefore, A = 1, B = 8, and C = -6.
The axis of symmetry is found using the equation -b/2a, as you've done. Therefore, the axis of symmetry is -8/2(1) = -4.
Hope this helps!! :)
Answer:
<h2>D. 6</h2>
Step-by-step explanation:
The formula of a distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have the points
and ![\left(-\dfrac{1}{2},\ 2\right)](https://tex.z-dn.net/?f=%5Cleft%28-%5Cdfrac%7B1%7D%7B2%7D%2C%5C%202%5Cright%29)
Substitute:
![d=\sqrt{\left(-\dfrac{1}{2}-\left(-\dfrac{1}{2}\right)\right)^2+(2-8)^2}=\sqrt{\left(-\dfrac{1}{2}+\dfrac{1}{2}\right)^2+(-6)^2}\\\\=\sqrt{0^2+36}=\sqrt{36}=6](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5Cleft%28-%5Cdfrac%7B1%7D%7B2%7D-%5Cleft%28-%5Cdfrac%7B1%7D%7B2%7D%5Cright%29%5Cright%29%5E2%2B%282-8%29%5E2%7D%3D%5Csqrt%7B%5Cleft%28-%5Cdfrac%7B1%7D%7B2%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Cright%29%5E2%2B%28-6%29%5E2%7D%5C%5C%5C%5C%3D%5Csqrt%7B0%5E2%2B36%7D%3D%5Csqrt%7B36%7D%3D6)
Answer:
-1=-2
4=-7
Step-by-step explanation:
for x=-1
y=(-1^2)+(2*-1)+1
y=-1-2+1
y=-2
for x=1
y= (-1^2)+(2*1)+1
y= -1+2+1
y=2
for x=4
y=(-4^2)+(2*4)+1
y=-16+8+1
y=-7
Picture is cropped. Can't see information.