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galina1969 [7]
3 years ago
8

Jenny likes to paint. She estimates the number of paintings she completes using the function P of w equals one half times w plus

one, where w is the number of weeks she spends painting. The function J(y) represents how many weeks per year she spends painting. Which composite function would represent how many paintings Jenny completes in a year?
A. P of J of y equals one half times J of y plus one
B. P of J of y equals J times the quantity one half times w plus one
C. J of P of w equals one half times J of y plus one
D. J of P of w equals J times the quantity one half times w plus one
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0
The answer to the question is A.
lubasha [3.4K]3 years ago
7 0

Answer:

the answer is A

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Solve w^2 + 7w - 18 = 0<br><br>with the steps pls​
Bess [88]

Answer:

w=2  w = -9

Step-by-step explanation:

w^2 + 7w - 18 = 0

We can factor this equation

What 2 numbers multiply to -18 and add to 7

9*-2 = -18

9+-2 = 7

(w-2) (w+9) = 0

Using the zero product property

w-2 = 0    w+9 =0

w=2  w = -9

4 0
2 years ago
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Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

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\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

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3 years ago
Find the common difference of the arithmetic sequence. 4,32/3,31/3,3<br> The common difference is
ale4655 [162]
2 is the common difference
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3 years ago
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Cloud [144]

Answer:

The answer to your question is: Yes, x - 5  is a factor of the polynomial.

Step-by-step explanation:

To answer this question you need  to divide the polynomial by the factor and if there is nothing left, they are factor.

                   

                             <u>x³ -4x² -7x +10</u>

                                      x -5

                         

                         x²  + x -2

              x-5      x³ -4x² -7x +10

                        -x³ + 5x²

                               x²  - 7x

                             -x²   + 5x

                                      -2x + 10

                                      +2x -10

                                         0     0       These zeros tell us that the linear

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5 0
3 years ago
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kiruha [24]

For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

We multiply both sides by: (\frac {1} {36}) ^ {3n}

216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}

We divide both sides by 216:

\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}

To divide powers of the same base, we place the same base and subtract the exponents:

216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}

Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

To multiply powers of the same base, we place the same base and add the exponents:

6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1

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So, for equality to be true:

9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1

Answer:

n = 1

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3 years ago
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