Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:
169
Step-by-step explanation:
PEMDAS
Parenthesis first
Add -1 and -3 which is -4
Divide 24 by 6 which is 4
(4-2+5*3*-4÷4)^2
(4-2-15)^2
(2-15)^2
(-13)^2
Which is 169
I think it's suppose to go
6% is .06 divided by 12 which is .005 times the number of months so in this case 9 so 5,000 times .005 times 9 which is 225 so 5,000 plus an interest of 225 adds up to 5,225
Answer:
The Y intercept is -5 and the slope is -5/2
Answer:
ok so the two other ways are- 6:2 and 9:3
And the second part- 5
Step-by-step explanation:
