Answer:
The probability that a manufactured ball will be rejected is 0.99, to two decimal places.
Step-by-step explanation:
The mean weight is 16 Ibs. The standard deviation of the weights of all manufactured balls from the mean weight is 25. The distribution is normal. With a standard deviation this large, it is already obvious that there is a high probability of producing or having rejected balls. The weights of the balls produced here ranges from (16-25)Ibs to (16+25)Ibs.
That's -9Ibs to 41Ibs.
The minimum permissible weight is 15.68. Any ball with a lesser weight gets kicked out!
So the distance or difference between this figure and the mean is (16-15.68) = 0.32
So the probability of obtaining less than 15.68Ibs or the probability of having balls between the lower boundary of -9Ibs and 15.68 is:
25-0.32 = 24.68
24.68 ÷ 25 = 0.9872 ~ 0.99 to two decimal places.
Answer:
6=6
Step-by-step explanation:
2x3=3x2
6=3x2
6=6
1/3n - 8 = -13 Is your equation
Your answer to the equation is
-13-8 = -21 times 1/3 is -13.86
N= -13.86
De acordo com a disponibilidade da unidade, há apenas a seguinte dosagem: 1g/2mL - ou seja, uma grama de dipirona a cada 2mL
O enunciado está meio mal formulado, pois é dito que foram prescritos 500mg de dipirona e é essa quantidade de farmaco que a criança tem que tomar. Deseja-se saber quantos mL deverao ser administrados.
Fazendo a classica regra de 3, podemos chegar no volume desejado:
(atentar que 500mg = 0,5g)
g mL
1 --------- 2
0,5 --------- X
1 . X = 0,5 . 2
<h3>X = 1mL</h3>
20 liters I looked up the answer and did research on how to find it.