Answer:
x = 2 + sqrt(2) or x = 2 - sqrt(2) thus B. is your answer
Step-by-step explanation:
Solve for x over the real numbers:
4 x^2 - 16 x + 8 = 0
Hint: | Write the quadratic equation in standard form.
Divide both sides by 4:
x^2 - 4 x + 2 = 0
Hint: | Solve the quadratic equation by completing the square.
Subtract 2 from both sides:
x^2 - 4 x = -2
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.
Add 4 to both sides:
x^2 - 4 x + 4 = 2
Hint: | Factor the left-hand side.
Write the left-hand side as a square:
(x - 2)^2 = 2
Hint: | Eliminate the exponent on the left-hand side.
Take the square root of both sides:
x - 2 = sqrt(2) or x - 2 = -sqrt(2)
Hint: | Look at the first equation: Solve for x.
Add 2 to both sides:
x = 2 + sqrt(2) or x - 2 = -sqrt(2)
Hint: | Look at the second equation: Solve for x.
Add 2 to both sides:
Answer: x = 2 + sqrt(2) or x = 2 - sqrt(2)
X=16 i graphed it !!!!!!!!!!!!
Answer:
Fouls > Average Fouls
Step-by-step explanation:
Null Hypothesis [ H0 ] : Fouls = Average Fouls ie 11.5
Alternate Hypothesis [ H1 ] : Fouls > Average Fouls
t = ( x - u ) / ( s / √n )
where x = actual observed mean = 12.2 here , u = assumed population mean = 11.5 , s = sample standard deviation = 1.6 , n = sample size = 34
So, t = (12.2 - 11.5 ) / ( 1.6 / √34 ) = 0.7 / ( 1.6 / 5.83 ) = 0.7 / 0.275 = 2.55
t tabulated value for α = 5% right tailed = 1.645 , ie < calculated value 2.55 So , we reject the null hypothesis, & conclude that 'Fouls > Average Fouls'
Answer:
Step-by-step explanation:
The following are the distances (in miles) to the nearest airport for 12 families. 6, 7, 8, 8, 16, 19, 23, 24, 26, 27, 34, 35 No
AveGali [126]
Using it's definitions, the five-number summary and the interquartile range for the data-set is given as follows:
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
- The interquartile range is the difference of the third quartile and the first quartile.
This data-set has 12 elements, which is an even number, hence the median is the mean of the 6th and 7th elements, as follows:
Me = (19 + 23)/2 = 21.
The first quartile is the median of 6, 7, 8, 8, 16, which is the third element of 8.
The third quartile is the median of 23, 24, 26, 27, 34, 35, which is of 27. Hence the interquartile range is of 27 - 8 = 19.
The minimum is the lowest value in the data-set, which is of 6, while the maximum is of 35, which is the largest value in the data-set.
More can be learned about the five-number summary and the interquartile range at brainly.com/question/3876456
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