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son4ous [18]
2 years ago
8

The following are the distances (in miles) to the nearest airport for 12 families. 6, 7, 8, 8, 16, 19, 23, 24, 26, 27, 34, 35 No

tice that the numbers are ordered from least to greatest. Give the five-number summary and the interquartile range for the data set. Five-number summary
Minimum:
Lower quartile:
Median:
Upper quartile:
Maximum:
Interquartile range:
Mathematics
1 answer:
AveGali [126]2 years ago
4 0

Using it's definitions, the five-number summary and the interquartile range for the data-set is given as follows:

  • Minimum: 6
  • Lower quartile: 8
  • Median: 21.
  • Upper quartile: 27
  • Maximum: 35
  • Interquartile range: 19

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the third quartile and the first quartile.

This data-set has 12 elements, which is an even number, hence the median is the mean of the 6th and 7th elements, as follows:

Me = (19 + 23)/2 = 21.

The first quartile is the median of 6, 7, 8, 8, 16, which is the third element of 8.

The third quartile is the median of 23, 24, 26, 27, 34, 35, which is of 27. Hence the interquartile range is of 27 - 8 = 19.

The minimum is the lowest value in the data-set, which is of 6, while the maximum is of 35, which is the largest value in the data-set.

More can be learned about the five-number summary and the interquartile range at brainly.com/question/3876456

#SPJ1

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Answer:

E + F =   2c^2  + 5c + 4

Step-by-step explanation:

E=6c^2-2c-1

F=-4c^2+7c+5

E+F=  6c^2   -2c   -1  +  -4c^2   +   7c   +  5

E + F =   6c^2 - 4c^2  - 2c + 7c  - 1  + 5

E + F =   2c^2  + 5c + 4

4 0
3 years ago
Math! Who’s knows the answer?
kykrilka [37]

Answer:

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Answer:

905

Step-by-step explanation:

So your original equation is f(x) = x² + 5

First lets work with the stuff inside the parentheses.

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So now you are finding,

f(f(5)) => f(30)

f(30) = 30² + 5 = 900 + 5 = 905

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