Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,

Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,

Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,

Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,

Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
2/5m - 4/5 - 3/5m...combine like terms
-1/5m - 4/5
Answer:
A 846 square inches
Step-by-step explanation:
Use the net:
Rectangle 1: (21 in + 3 in + 21 in + 3 in) by 15 in.
Rectangle 2: 21 in by 3 in
Rectangle 3: 21 in by 3 in
total area = sum of areas of 3 rectangles above.
total area = (48 in * 15 in) + 2(21 in * 3 in)
total area = 720 in^2 + 126 in^2
total area = 801 in^2
Answer: A 846 square inches