Answer:
seis CM para 10 yd por eso
Step-by-step explanation:
y + 4 = -2x + 2
2x + y = -2
2x = -2 - y
x = -2 -y/2
The is it mean, range, mode, or median of the following set of data is 6. 13, 7, 9, 5, 2, 3, 5, 4, 10, 12
grandymaker [24]
the way you have laid this question out is strange but im assuming you want me to find the mean, range, medium and mode of the numbers provided?
<h2>
Answer:</h2>
median=order them and find the middle= <u><em>6</em></u>
mean=add them all up and divide by the amount of numbers=(6+13+7+9+5+3+2+5+4+10+12)/11=<em><u>6.9</u></em>
range= the difference between the smallest and largest number=13-2=<u><em>11</em></u>
mode= the one that appears the most= <em><u>5</u></em>
Given:
The probability of drawing a red candy at random from a bag of 25 candies is 
.
To find:
The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.
Solution:
Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:
After removing the 5 candies from the bag, the number of remaining candies is 
and the number of remaining red candies is 
.
Now, the probability of randomly drawing a red candy from the bag is:
Therefore, the required probability is 
.
