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Anna71 [15]
3 years ago
13

The cost of downloading a book from a certain website is $5.99. The cost of downloading a video is $7.99. Tatum's mom downloads

3 books and 5 videos. How much did she spend on downloads?
Mathematics
2 answers:
jekas [21]3 years ago
6 0
The easiest way to answer this question is by rounding $5.99 and $7.99 to $6.00 and $8.00. Then multiply 3 by 6 and 5 by 8. 3 * 6 = 9 5 * 8 = 40 40 + 9 = 49. Now to find the exact answer, seeing as $5.99 is 1 cent away from $6.00 and $7.99 is one cent away from $8.00, we can do 3 * 1 = 3 and 5 * 1 = 5 3 + 5 = 8, we can see that $49 is 8 cents over. From there we subtract the 8 cents from the $49 and see that the amount she spent on downloads was $48.92.
zaharov [31]3 years ago
4 0
The Answer Is 57.92 But the easiest way to do it is Rounding it
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What does 4 + 5 equal
Svet_ta [14]

Answer:

9

Step-by-step explanation:

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3 years ago
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Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
3 years ago
The quotient of y and 6 is 29 find the value of y
atroni [7]
Y÷6=29
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Hope I can help u
7 0
3 years ago
4/5 to a decimal using an equivalent fraction
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8/10 is equivalent to 4/5.
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Mariana [72]
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