[area of a regular hexagon]=6*[area of one <span>equilateral triangle] </span>210.44=6*[area of one equilateral triangle] [area of one equilateral triangle]=210.44/6-----> 35.07 cm²
[area of one equilateral triangle]=b*h/2 h=7.794 cm b=2*area/h------> b=2*35.07/7.794------>b= 9 cm
the length side of a regular hexagon is 9 cm <span>applying the Pythagorean theorem </span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm
<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles) </span> the answer is the radius is 9 cm
