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Gala2k [10]
2 years ago
11

The angles of a quadrilateral have measures m∠A = (7x)◦, m∠B = (4x + 5)◦, m∠C =

Mathematics
1 answer:
tino4ka555 [31]2 years ago
4 0

The value of x is 15° and the type of quadrilateral is a rhombus.

<h3>Quadrilateral</h3>

  • A quadrilateral is a polygon that has four sides.
  • The sum of all angles of a quadrilateral is 360°.

Here, we are given,

m∠A = (7x)◦, m∠B = (4x + 5)◦, m∠C =(6x + 15)◦, m∠D = (6x −5)◦

So, we will have

7x+4x+5+6x+15+6x-5=360°

23x+15°=360°

23x=345°

x=345°/23°

x=15°

Hence, the angles of the quadrilateral are:

m∠A = (7x)◦=105°,

m∠B = (4x + 5)◦ =65°

m∠C =105°

m∠D = (6x −5)◦ =85°

Since the diagonal bisects ∠B and ∠D, we get that the quadrilateral is a rhombus.

To learn more about rhombus refer to:

brainly.com/question/27870968

#SPJ10

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1. Answer:

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<u>Step-by-step explanation:</u>

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y = 0.20(0) + 70   →   y = 0.00 + 70   →   y = 70.00

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*******************************************************************************

2. Answer:

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<u>Step-by-step explanation:</u>

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4. Answer: Gym A → y = 20x + 50    Gym B → y = 25x + 30

<u>Step-by-step explanation:</u>

Use the slope formula: m = \dfrac{y_2-y_1}{x_2-x_1}.  Then choose ONE of the points and input the point (x₁, y₁) and slope (m) into the Point-Slope formula: y - y₁ = m(x - x₁) and solve for y.

Gym A: (x₁, y₁) = (1, 70) and (x₂, y₂) = (2, 90)

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y - 55 = 25x - 25

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