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2 years ago

Help me get these 10 questions u will have 100 points EZ

Mathematics

1 answer:

ololo11 [35]2 years ago

6 0

B:has a inverse function because it’s graph passes the vertical line test

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Which expression is equivalent to 2 (a + 3) when a = 3? 2 (3) 5 (3) 2 (3) + 3 2 (3) + 6

kenny6666 [7]

2(3)+6

Explanation

2(3+3)=12

2(3)+6
6+6=12

Equivalent

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3 years ago

If you ate 56 hotdogs in 7 minutes how much would you eat per minute

Elan Coil [88]

Answer:

8 hot dogs

Step-by-step explanation:

$8*7=56\\$

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3 years ago

Read 2 more answers

Find the missing factor. Mn+2n+n^2+2m= (n+2) ( )

Citrus2011 [14]

I think your answer is m=-n-1

3 0

3 years ago

2. Please complete both Parts A, B, & C below.

Vladimir [108]

Answer:

a)ab and yz, ac and xy, bc and xz

b)yz = xy = xz 30 = 37.5 = 45 3 = 3 = 3

ab ac bc 40 50 60 4 4 4

c)they are similar because all sides break down to ¾

Step-by-step explanation: i did this on my test

6 0

3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago