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pochemuha
2 years ago
11

Help me get these 10 questions u will have 100 points EZ

Mathematics
1 answer:
ololo11 [35]2 years ago
6 0
B:has a inverse function because it’s graph passes the vertical line test
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Which expression is equivalent to 2 (a + 3) when a = 3? 2 (3) 5 (3) 2 (3) + 3 2 (3) + 6
kenny6666 [7]
2(3)+6

Explanation

2(3+3)=12


2(3)+6
6+6=12

Equivalent
5 0
3 years ago
If you ate 56 hotdogs in 7 minutes how much would you eat per minute
Elan Coil [88]

Answer:

8 hot dogs

Step-by-step explanation:

8*7=56\\

6 0
3 years ago
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Find the missing factor. Mn+2n+n^2+2m= (n+2) ( )
Citrus2011 [14]
I think your answer is m=-n-1
3 0
3 years ago
2. Please complete both Parts A, B, & C below.
Vladimir [108]

Answer:

a)ab and yz, ac and xy, bc and xz

b)yz  =   xy  =   xz          30 = 37.5 = 45      3 = 3 = 3      

ab      ac        bc          40     50       60     4    4    4

c)they are similar because all sides break down to ¾  

Step-by-step explanation: i did this on my test

6 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
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