Answer:
The answers to the questions are;
(a) P(At least 1 defective)
= 0.9883.
(b) P(At least 1 defective)
= 0.6409.
Step-by-step explanation:
There are 110 cards and 20 defectives.
a) The probability of at least one defective is given by
P(At least 1 defective) = 1 - P(0 defective)
P(0 defective) = 20C0 × (90C0)/(110C20) = 0.0116
1 - 0.0116 = 0.9883
b) For a set of 110 boards that has 5 defective and 105 non-defective
P(At least 1 defective) = 1 - P(0 defective)
P(0 defective) = (20C0)(90C5)/(110C5) = 0.35909
1-0.35909
= 0.6409
Volume
= 1/3 x Area x Height
= 1/3 x 110(Approximately) x 16
≈ 588.8 m^3
Answer is 588.8 m^3.
Hope it helps
35 percent is the answer to ur problem sir
Answer:
10
Step-by-step explanation: you have five fingers and another five fingers and when you put them together you have ten
