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2 years ago

5/9 divide 5 in the simplest form

Mathematics

2 answers:

dimulka [17.4K]2 years ago

6 0

$\: \: \: \: \: \:$

$= \frac{1}{9} \\ \\ or \: \: in \: \: alternate \: form \: \: \\ \\ 0.1, {3}^{ - 2}$

<h2 />

Step-by-step explanation:

$\frac{5}{9} \div 5$

dividing the equivalent to multiplying by the reciprocal

$\frac{5}{9} \times \frac{1}{5}$

reduce the numbers with the greatest common factor 5

$= \frac{1}{9} \: \: \\ \\ or \: \: in \: \: alternate \: \: form \\ \\ 0.1, {3}^{ - 2}$

<h2>hope it helps</h2>

serious [3.7K]2 years ago

3 0

Ok done. Thank to me :>

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In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

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900% of it is 450 ? please help with this

charle [14.2K]

900% of 450=4050

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 450 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 450 is 100%, so we can write it down as 450=100%.
4. We know, that x is 900% of the output value, so we can write it down as x=900%.
5. Now we have two simple equations:
1) 450=100%
2) x=900%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
450/x=100%/900%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 900% of 450

450/x=100/900
(450/x)*x=(100/900)*x - we multiply both sides of the equation by x
450=0.111111111111*x - we divide both sides of the equation by (0.111111111111) to get x
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Answer:

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