Whenever you want to write the equation of a parallel line through some point (h, k), you can ...
- remove any added constant in the original given equation
- replace x with (x-h)
- replace y with (y-k)
- rearrange the resulting equation to the form required by the problem.
Using this formula here, we get
... 2(y +5) = 3(x -2)
Your answer form requires you solve this for y.
... 2y + 10 = 3x -6 . . . . . eliminate parentheses
... 2y = 3x -16 . . . . . . . . subtract the constant on the left (10)
... y = (3/2)x -8 . . . . . . divide by 2
Answer:
3¹² is answer
Step-by-step explanation:
3^(2+4+6)
3^12
Answer:
,
Step-by-step explanation:
,...
Answer:
=========
<h2>Given</h2>
<h3>Line 1</h3>
<h3>Line 2</h3>
- Passing through the points (4, 3) and (5, - 3)
<h2>To find</h2>
- The value of k, if the lines are perpendicular
<h2>Solution</h2>
We know the perpendicular lines have opposite reciprocal slopes, that is the product of their slopes is - 1.
Find the slope of line 1 by converting the equation into slope-intercept from standard form:
<u><em>Info:</em></u>
- <em>standard form is ⇒ ax + by + c = 0, </em>
- <em>slope - intercept form is ⇒ y = mx + b, where m is the slope</em>
- 3x - ky + 7 = 0
- ky = 3x + 7
- y = (3/k)x + 7/k
Its slope is 3/k.
Find the slope of line 2, using the slope formula:
- m = (y₂ - y₁)/(x₂ - x₁) = (-3 - 3)/(5 - 4) = - 6/1 = - 6
We have both the slopes now. Find their product:
- (3/k)*(- 6) = - 1
- - 18/k = - 1
- k = 18
So when k is 18, the lines are perpendicular.
