A square pyramid is called like so because its base is a square.
notice this one, its base is a 0.4x0.4 square, and the triangular faces have a base of 0.4 and an altitude or height of 5.
so we can simply get the area of the base and all four triangular faces and sum them up, and that's the surface area of the pyramid.
1 st hit=12 ft
2nd hit=2*6=12 ft
3rd hit=2*3=6 ft
4th hit=2*1.5=3 ft
total distance=12+12+6+3=33 ft
Answer:
m<JKD = 22 degrees
Step-by-step explanation:
21x + 5 + 4x + 2 = 132
25x + 7 = 132
25x = 125
x = 5
m<JKD = 4x + 2
4(5) + 2
20 + 2
22
Start by integrating y'' twice to get function y(x).

Next find value of coefficients 'c' and 'd' using the given tangent line
The slope of tangent line is equal to y' when x=1.

The tangent line intersects the curve y(x) when x = 1.
If x = 1, then y = 4 (From y =-x+5)

Final Answer: