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dem82 [27]
1 year ago
7

Can someone pls help me?

Mathematics
1 answer:
kirza4 [7]1 year ago
5 0

Answer:

\frac{8}{24}

Step-by-step explanation:

If Adam's family uses 8lb of apples to make pie. We know that 3 x 8 = 24, so it's probably approximately 3 out of 18.

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Slope-intercept form of Slope = -9/5, y-intercept = -4
Brilliant_brown [7]

Answer:

y = - \frac{9}{5} x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{9}{5} and c = - 4 , thus

y = - \frac{9}{5} x - 4 ← equation of line

7 0
2 years ago
Michael Pedro and Kevin were saving money. All together they saved $130. Kevin saved 3 times more than Pedro. Michael saved $20
yKpoI14uk [10]

Answer:

The saving of all three person are

The Pedro's saving is $ 30

The Michael's saving is $ 10

The Kevin's saving is $ 90

Step-by-step explanation:

Given as :

The three person namely Michael , Pedro , Kevin

The total saving of all together = $ 130

Let The Michael's saving = $ M

The Pedro's saving = $ P

The Kevin's saving = $ k

I.e Michael's saving + Pedro's saving + Kevin's saving = $ 130

Or, M + P + K = $ 130

again ,

Kevin saved 3 times more than Pedro

I.e K = 3 × P

And , Michael save $ 20 less than Pedro

I.e M = P - $ 20

Now

∵ M + P + K = $ 130

or, (  P - $ 20) + P + 3 × P = $ 130

Or, 5 P - $ 20 = $ 130

Or, 5 P = $ 130 + $ 20

Or, 5 P = $ 150

∴ P = $ \frac{150}{5}

I.e P = $ 30

So The Pedro's saving = P = $ 30

And

M = P - $ 20

∴, M = $ 30 - $ 20

I.e M = $ 10

So,  The Michael's saving = M = $ 10

Similarly

K = 3 × P

∴ k = 3 × $ 30

I.e K = $ 90

So, The Kevin's saving = k = $ 90

Hence The saving of all three person are

The Pedro's saving is $ 30

The Michael's saving is $ 10

The Kevin's saving is $ 90

Answer

5 0
3 years ago
In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146

P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

6 0
3 years ago
3(7v-5)-v(10v-9) how do is solve this problem
Alika [10]

3(7v-5)-v(10v-9) = 21v - 15 -10v² + 9v = - 10v² + 30v - 15

8 0
3 years ago
8. A cent is 0.01 of a dollar
Oksanka [162]

Answer:

Yes

Step-by-step explanation:

A dollar = 100 cents

1 cent : 100 cents

= 1/100

= 0.01

8 0
2 years ago
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