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Charra [1.4K]
3 years ago
12

What is the equation of an exponential function with base=2 that has a vertical stretch by a factor of 3, a shift to the right 5

and a shift up 6 ?
Mathematics
1 answer:
il63 [147K]3 years ago
7 0

Answer:

y=3(2)^{x-5}+6

Step-by-step explanation:

Let the equation of the exponential function with base 2 is,

y=a(2)^{x+c}+d

Here, a = vertical stretch

c = Horizontal shift

d = Vertical shift

If this function has a vertical stretch by a factor of 3,

Equation will be,

y=3(2)^{x+c}+d

If this function has a shift of 5 to the right,

Equation of the function will be,

y=3(2)^{x-5}+d

If this function has a shift of 6 units upwards,

y=3(2)^{x-5}+6

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Solve each quadratic equation by factoring and using the zero product property.
Iteru [2.4K]

Answer:

x=5                            x=6

Step-by-step explanation:

x^2 - 8x + 30 = 3x

Subtract 3x from each side

x^2 - 8x-3x + 30 = 3x-3x

x^2 - 11x + 30 = 0

What 2 numbers multiply to 30 and add to -11

-5*-6 = 30

-5+-6 = -11

(x-5) (x-6) =0

Using the zero product property

x-5 = 0  and x-6 =0

x-5+5 =0+5   and x-6+6 =0+6

x=5                            x=6

7 0
4 years ago
Read 2 more answers
En un distrito, hay una calle peatonal. El municipio decidió colocar faroles, bancas y sembrar árboles para mejorar el ornamento
olga_2 [115]

Answer:

El lugar donde la linterna, los bancos y los árboles se encuentran nuevamente está a 300 metros del punto de inicio.

Step-by-step explanation:

Los parámetros dados son;

El espacio entre las linternas = 30 metros.

El espacio entre los bancos = 20 metros.

El espacio entre los árboles = 50 metros.

Por lo tanto, tenemos, la ubicación donde la linterna, los bancos y los árboles se encuentran nuevamente, está dada por el mínimo común múltiplo de cada una de sus distancias de separación individuales como sigue;

      2   divide   30   20   50 {}  

{}      <u>5  divide    15    10    25</u>

{}                           3      2    5

El LCM = 2 × 5 × 3 × 2 × 5 = 300

El lugar donde la linterna, los bancos y los árboles se vuelven a encontrar está a 300 metros del punto de inicio.

6 0
3 years ago
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