Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
3.16666667 tons
Step-by-step explanation:
hope this helps have a good evening
It should be B because it’s going down 4
Answer:
When a line gets closer to a horizontal asymptote, the the y value decreases, but the y value is never equals the value of the asymptote
Step-by-step explanation:
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The answer is -7, because a whole number is any number between zero and POSITIVE infinity. Negative seven does not fall under this.
