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2 years ago

Square ABCD has points A(5, 10) and B(-4, 3). What is the slope of line segment BC?

Mathematics

1 answer:

Alexxandr [17]2 years ago

6 0

Answer:

Step-by-step explanation:

9/7

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AVprozaik [17]

Step-by-step explanation:

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3 years ago

Help I can’t figure out how to do zero exponents

Orlov [11]

Anything (except 0) to the 0 power is equal to 1.

8^0 = 1

(-8)^0 = 1

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4 0

2 years ago

What is this answer???

wlad13 [49]

Answer:

∠ ABC = 116°

Step-by-step explanation:

Since the angles are supplementary, they sum to 180° , that is

8x - 36 + 4x - 12 = 180

12x - 48 = 180 ( add 48 to both sides )

12x = 228 ( divide both sides by 12 )

x = 19

Then

∠ ABC = 8x - 36 = 8(19) - 36 = 152 - 36 = 116°

5 0

2 years ago

1) Find the slope. 2) write an equation

hodyreva [135]

Answer:

Well, 10

Step-by-step explanation:

Because I am SMART

5 0

2 years ago

Use the quadratic formula to solve for x. 4x2 +9x-1=0

insens350 [35]

Answer:

$x=\frac{-9\pm\sqrt{65} }{8}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define

4x² + 9x - 1 = 0

Step 2: Define variables

a = 4

b = 9

c = -1

Step 3: Find roots

Substitute: $x=\frac{-9\pm\sqrt{9^2-4(4)(-1)} }{2(4)}$
Exponents: $x=\frac{-9\pm\sqrt{81-4(4)(-1)} }{2(4)}$
Multiply: $x=\frac{-9\pm\sqrt{81-16} }{8}$
Subtract: $x=\frac{-9\pm\sqrt{65} }{8}$

5 0

2 years ago