Question

A particular sawdust pile has a base diameter of 25 feet when the height is 20 feet. Find the volume of this sawdust pile when it is 30 feet high.

Answer 1

The volume of the sawdust pile is 11,039.06 ft³.

What is the volume of the pile?

The shape of the sawdust pile would be a cone. The diameter is always proportional to its height.

Diameter = k x height

where k is equivalent to the rate of increase of the diameter with respect to the increase in height.

25= k20

k = 25 / 20

k = 1.25

Diameter when height is 30 ft = 1.25x 30 = 35.50 feet

Volume of the sawdust = $\frac{1}{3}$πr²h

Where:

• π = 3.14
• r = radius = diameter / 2 = 35.50 / 2 = 18.75
• h = 30

$\frac{1}{3}$ x 3.14 x 18.75² x 30 = 11,039.06 ft³

To learn more about the volume of a cone, please check: brainly.com/question/13705125

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