A particular sawdust pile has a base diameter of 25 feet when the height is 20 feet. Find the volume of this sawdust pile when i
1 answer:
The volume of the sawdust pile is 11,039.06 ft³.
<h3>What is the volume of the pile?</h3>
The shape of the sawdust pile would be a cone. The diameter is always proportional to its height.
Diameter = k x height
where k is equivalent to the rate of increase of the diameter with respect to the increase in height.
25= k20
k = 25 / 20
k = 1.25
Diameter when height is 30 ft = 1.25x 30 = 35.50 feet
Volume of the sawdust = πr²h
Where:
- π = 3.14
- r = radius = diameter / 2 = 35.50 / 2 = 18.75
- h = 30
x 3.14 x 18.75² x 30 = 11,039.06 ft³
To learn more about the volume of a cone, please check: brainly.com/question/13705125
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ANSWER
45.6cm to the nearest tenth.
EXPLANATION
The diagonal of the rectangular painting is 62cm.
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From the Pythagoras Theorem,
The width of the painting is 45.6cm to the nearest tenth.
It is given that the area of the circular garden = 100
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We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.
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So, r = 5.6 ft
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Therefore, the approximate distance from the edge of Frank’s garden to the center of the garden is 6 ft.
So, Option A is the correct answer.