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3 years ago

Lowell bought 4 1/4 pounds of apples and 3 3/5 pounds of oranges. How many pounds of fruit did Lowell boy?

Mathematics

2 answers:

Serjik [45]3 years ago

8 0

7 17/20

You add the fractions together and then simplify the answer

Zolol [24]3 years ago

6 0

$\bf 4\frac{1}{4}\implies \cfrac{4\cdot 4+1}{4}\implies \cfrac{9}{4}
\\\\\\
3\frac{3}{5}\implies \cfrac{3\cdot 5+3}{5}\implies \cfrac{18}{5}\\\\
-------------------------------\\\\
\cfrac{9}{4}+\cfrac{18}{5}\impliedby \textit{we'll use the LCD of 20}\implies \cfrac{(5\cdot 9)~+~(4\cdot 18)}{20}
\\\\\\
\cfrac{45+72}{20}\implies \cfrac{117}{20}\implies 5\frac{17}{20}$

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A quiz has thirty questions whose answers can only be correct or incorrect.

satela [25.4K]

Using a system of equations, it is found that Gina got 22 questions correct in the test.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

Variable x: Number of questions she got correct.

Variable y: Number of questions she got wrong.

The test has 30 questions, hence:

x + y = 30 -> y = 30 - x.

She scored 152 points, hence, considering the value of each question:

8x - 3y = 152.

Since y = 30 - x:

8x - 3(30 - x) = 152

11x = 242

x = 242/11

x = 22

Gina got 22 questions correct in the test.

More can be learned about a system of equations at brainly.com/question/24342899

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2 years ago

Allison had a 1/4 of a whole pizza and wants to divided it equally for herself and five of her friends. How much does each frien

IRINA_888 [86]

i believe it is 1/3. but check other sources as well.

5 0

3 years ago

Read 2 more answers

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago

An artist wants to frame a square painting with an area of 400 square inches if x is the length of the one side of the painting

tatuchka [14]

There is only one solution to the equation. A quadratic equation has 2 solutions a positive and a negative, but since we are looking for length, the answer can only be postive. Area= side^2

400= x^2

sqrt(400)=x

20 inches = x

The length of one side is 20 inches

check: 20*20 = 400, which is the area of the square painting.

8 0

3 years ago

At a fundraiser, students sold chocolate bars with almonds and chocolate bars with walnuts. The number of chocolate bars with al

BabaBlast [244]

Answer:

Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

Step-by-step explanation:

Let number chocolate bars with almonds be x

Also let number chocolate bars with walnuts be y

Given:

Number of chocolate bars with almonds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts.

Framing the above sentence in equation form we get;

$x=2y -3$

Also given:

The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300.

Framing the above sentence in equation form we get;

$4x+y=300$

Now Substituting the value of x in above equation we get;

$4x+y=300\\4(2y-3)+y=300\\8y-12+y=300\\9y=300+12\\9y=312\\\\y=\frac{312}{9} \approx 34.67$

Now we will substitute the value of y in equation $x=2y -3$ we get;

$x=2y-3 = 2\times34.67 -3 = 69.34-3\approx66.34$

Hence, Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

6 0

4 years ago