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LekaFEV [45]
2 years ago
15

A box has twice as many grapes as a basket. Once 2kg of grapes were added to the basket, it contained 0.5 kg more than the box.

How many kilograms of grapes are in the basket now?
Mathematics
1 answer:
pav-90 [236]2 years ago
3 0

By solving a system of equations, we will see that now there are 3.5kg of grapes on the basket.

<h3>How many kilograms of grapes are in the basket now?</h3>

Let's define the variables:

  • x = kg of grapes on the box originally.
  • y = kg of grapes on the basket originally.

We know that:

x = 2y

When we add 2kg to the basket, it has 0.5k more than the box, then:

y + 2 = x + 0.5

Then we have a system of equations:

x = 2y

y + 2 = x + 0.5

We want to solve this for y, then we can replace the first equation into the second one:

y + 2 = (x = 2y) + 0.5

y + 2 = 2y + 0.5

2 - 0.5 = 2y - y

1.5 = y

This means that, originally, there are 1.5 kg of grapes on the basket. And then we added 2kg, so now there are:

1.5kg + 2kg = 3.5kg

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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A greeting card company can produce a box of cards for $7.50. If the initial investment by the company was $50,000, how many box
larisa86 [58]

Answer:

If cost of one box of card is $7.50 then the no of cards produced is 6667 cards and if cost of one box of card is $10.50 then the no of cards produced is 4762 cards

Step-by-step explanation:

The cost of one box of cards = $7.50

Initial investment = $50,000

No of box of cards produced = Initial investment / cost of one box of card

No of box of cards produced = 50,000/7.50

No of box of cards produced = 6667 cards.

if the cost of one box of cards is increased = $10.50

No of box of cards produced = Initial investment / cost of one box of card

No of box of cards produced = 50,000/10.50

No of box of cards produced = 4762 cards.

So, if cost of one box of card is $7.50 then the no of cards produced is 6667 cards and if cost of one box of card is $10.50 then the no of cards produced is 4762 cards

5 0
4 years ago
X^2-3=0 solve for all real values of x
sineoko [7]

Step-by-step explanation:

x²-3=0

x²=3

x=√3

<h2>stay safe healthy and happy.</h2>
3 0
3 years ago
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The corners of the vertices of CDE are c(1,4) d(3,7) e(7,4). if a triangle is reflected over the line y=3 what are the coordinat
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7 0
4 years ago
Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).
ki77a [65]

The magnitude of YZ is 8.6

<u>Explanation:</u>

<u />

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the value we get:

YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6

Thus, the magnitude of YZ is 8.6

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prohojiy [21]
Move everything to one side
Equation
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