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LekaFEV [45]
1 year ago
15

A box has twice as many grapes as a basket. Once 2kg of grapes were added to the basket, it contained 0.5 kg more than the box.

How many kilograms of grapes are in the basket now?
Mathematics
1 answer:
pav-90 [236]1 year ago
3 0

By solving a system of equations, we will see that now there are 3.5kg of grapes on the basket.

<h3>How many kilograms of grapes are in the basket now?</h3>

Let's define the variables:

  • x = kg of grapes on the box originally.
  • y = kg of grapes on the basket originally.

We know that:

x = 2y

When we add 2kg to the basket, it has 0.5k more than the box, then:

y + 2 = x + 0.5

Then we have a system of equations:

x = 2y

y + 2 = x + 0.5

We want to solve this for y, then we can replace the first equation into the second one:

y + 2 = (x = 2y) + 0.5

y + 2 = 2y + 0.5

2 - 0.5 = 2y - y

1.5 = y

This means that, originally, there are 1.5 kg of grapes on the basket. And then we added 2kg, so now there are:

1.5kg + 2kg = 3.5kg

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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Tell whether the ordered pair is a solution to the equation.<br><br><br> (1, 3); 4x – 3y = -5
Bumek [7]

Answer:

Yes

Step-by-step explanation:

4(1)-3(3)=-5

4-9=-5

-5=-5

8 0
2 years ago
^^^^<br> please help :)))
ikadub [295]

2x-1.1/4+x/3=2

2x-1/4+x/3=2

2x-1/4+x/3+1/4=2+1/4

2x+x/3=9/4

3(2x+x/3)=3.94

7x=27/4

7x/7=27/4/7

x=27/8

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7 0
2 years ago
In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
Tems11 [23]

Answer:  3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: n(E\cup N=50)

n(E)=46\\\\n(N)=7

For any two event A and B, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)

Similarly , n(E\cup N)=n(E)+n(N)-n(E\cap N)

50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3

Hence, 3 students have piercings both on their ears and their noses.

7 0
3 years ago
[4 - (3c - 1)][6 - ( 3c - 1)]
Anestetic [448]
Hi there!

You would have to simplify the terms inside [ ] this thing, then multiply.

So let's simplify them first.

4 - (3c - 1) 
use distributive property.....
4 - 3c + 1
-3c + 5

6 - (3c - 1)
use distributive property again...
6 - 3c + 1
-3c + 7

so now, multiply (-3c + 5)(-3c + 7).
(-3c + 5)(-3c + 7)
9c² - 21c - 15c + 35
9c² - 36c + 35

So your final answer is...
9c² - 36c + 35

Hope this helped! :)
3 0
3 years ago
Read 2 more answers
Write a quadratic equation for a parabola with roots at (-2, 0) &amp; (4,0) and a y-intercept at ( 0, -16) Write your answer in
meriva

9514 1404 393

Answer:

  y = 2(x +2)(x -4)

Step-by-step explanation:

The y-intercept will be a constant times the product of the roots. Here, the product of the roots is (-2)(4) = -8, so the constant of interest is -16/-8 = 2. That constant is the coefficient of the leading term of the quadratic, so is a multiplier of the factored form.

  y = 2(x +2)(x -4)

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For root p, (x-p) is a factor in the factored form.

8 0
2 years ago
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