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Cerrena [4.2K]
2 years ago
12

Find the value of b.

Mathematics
1 answer:
Nesterboy [21]2 years ago
7 0

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

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Here are two polygons on a grid. Is PQRST a scaled copy of ABCDE?
Bezzdna [24]

*see attachment showing the two polygons in a grid.

Answer:

No, PQRST is not a scale copy of ABCDE because we the sides are not increased proportionally.

Step-by-step explanation:

A polygon can be said to be a scaled copy of another polygon, if the the same scale factor is used in scaling every segment of the preimage or original image to get the length of the corresponding segments of the scale copy or image. In order words, all segments must be scaled proportionally.

Polygon PQRST, which is the new image, has different scale factors used in scaling the various segments of the preimage. In simple terms, the sides of PQRST were not increased proportionally. Therefore, PQRST is not a scaled copy of ABCDE.

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3 years ago
I) Construct a triangle PQR such that |PQ|=8cm,{RPQ=90°{PQR=30°.Measure |RQ|​
scoray [572]

Answer:

6.93 cm

Step-by-step explanation:

You have a right triangle (90°), so you do as follow:

If I understand correctly, you are looking for the hypotenuse so

cos(30) = \frac{PQ}{QR} = \frac{8 cm}{QR}

That is equal to QR = cos(30)*8 cm = 6.928 cm

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3 years ago
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ch4aika [34]
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Suppose (1,19) is on the graph of y = f (x). Which of the following points lies on the graph of the transformed function y = f(1
o-na [289]

Answer:

(5,19) lies on the graph of the transformed function y = f(1/5x)

Step-by-step explanation:

Suppose (1,19) is on the graph of y = f (x)

the graph of the transformed function y = f(1/5x)

y=f(\frac{1}{5}x)

1/5 is multiplied with x  in f(x)

1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5

To make horizontal stretch we change the point

f(x)=f(bx) then (x,y) --->( x/b,y)

We divide the x coordinate by the fraction 1/5

(1,19) ----> (\frac{1}{\frac{1}{5}} , 19)= (5,19)

So (5,19) lies on the graph of the transformed function y = f(1/5x)

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3 years ago
Cristy has ten pets including cats, birds, and hamsters. She has twice as many hamsters as cats.
marysya [2.9K]
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H = 4 C = 4 B = 2

6*4 + 3*4 + 1*2 = 38

Hope this helped :)
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