Answer:
Answer is 
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.
Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.
Answer:
A yard sale.
Step-by-step explanation:
lol
Answer:
11 and 12
Step-by-step explanation:
x(x+1)=132
x^2+x=132
x^2+x-132=0
(x-11)(x+12)=0
x = 11 or x = -12
when x=11 ,
x+1=12
11*12=132
2 x 3 = 6 x 10 = 60
<em>Assuming that you are using the same rule:
</em><em>4 x 9 x 10 = 360
</em>The value of z when x = 4 and y = 9 is 360. Hope this helped!
<span>1st number = 11, 2nd number = 5.5, 3rd number = -5.5</span>
