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Firdavs [7]
2 years ago
15

Find the roots of x^4-1=0​

Mathematics
1 answer:
serg [7]2 years ago
7 0

Answer:

x = +1

x = -1

Step-by-step explanation:

x^4-1=0​

x^4=+1​

fourth root of x^4= fourth root of +1​

x = +1

x = -1

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Winona’s bowling scores for the past nine weeks are 195, 180, 195, 212, 208, 231, 179, 246, and 195. Find the mean, median, and
belka [17]

Answer: Mean = 204.6  , Median = 195 and mode =195

Step-by-step explanation:

The given data for Winona’s bowling scores for the past nine weeks : 195, 180, 195, 212, 208, 231, 179, 246,  195.

The formula to find Mean is given by :-

\text{Mean}=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}\\\\=\dfrac{1841}{9}=204.555555556\approx204.6

For median , first we arrange data values in order as

179, 180, 195, 195, 195, 208, 212, 231, 246

Since the number of data values is 9 (odd).

∴ Median = Middle most data value = 195

Also, Mode = Most occurring data value = 195

3 0
3 years ago
A 12-pound bag weighs more than a 200-ounce bag. True or false
Anastasy [175]

Answer:

false

Step-by-step explanation:

200oz= 12.5 pounds

7 0
3 years ago
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Jake tutors students. He charges $10 for the first session and $5 for each additional session. Let x
SIZIF [17.4K]

Answer: y = 5x + 10

Step-by-step explanation:

y= 5x + 10

THINK ABOUT IT! if 5 is for EACH additional session and x is equal to the NUMBER OF SESSIONS...... then 5 times x will give you the cost for each additional session, but NOT INCLUDING THE 10 FOR THE FIRST SESSION. so simply just do 5x + 10 and y is the total cost so

y = 5x + 10

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2 years ago
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17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

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Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8   when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

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3 years ago
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I have a geometry pre course test I need help
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Answer:

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