Answer:
<h3><u>Question 7</u></h3>
<u>Lateral Surface Area</u>
The bases of a triangular prism are the triangles.
Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

<u>Total Surface Area</u>
Area of the isosceles triangle:

Total surface area:

<u>Volume</u>

<h3><u>Question 8</u></h3>
<u>Lateral Surface Area</u>
The bases of a hexagonal prism are the pentagons.
Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

<u>Total Surface Area</u>
Area of a pentagon:

where a is the side length.
Therefore:

Total surface area:

<u>Volume</u>

Answer:
659.6 ft
Step-by-step explanation:
x = 140 / tan 23
x = 329.82(rounded to hundredth)
so total ground distance between the cables = 2x = 2(329.82) = 659.64 feet
sorry misread the question
Answer:
744 cubic inches
Step-by-step explanation:
Volume of Styrofoam= volume of big box -volume of glass box
=(10*10*15)-(9*7*12)
=1500-756
=744 cubic inches
Answer:
4
Step-by-step explanation:
x^2/ y^4
Let x=8 and y=2
8^2 / 2^4
PEMDAS says powers first
64 / 16
Divide next
4