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BaLLatris [955]
1 year ago
11

How to convert whole number as fraction​

Mathematics
2 answers:
Mice21 [21]1 year ago
3 0

To <u>convert an integer to a fraction</u> you must choose an expression that does not alter the numerical value. You can do this with multiples of the number, for example, for 100:

100/1 = 200/2 = 300/3 = 400/4 = 100

  • The numerical value is not altered and the result will always be 100

Another example, for 500:

500 = 500/1 = 1000/2 = 1500/3 = 2000/4

<h2>{ Pisces04 }</h2>
netineya [11]1 year ago
3 0

Answer:

Step-by-step explanation:I actually depends on what your solving like if you are solving a question is says solving 16 times a random fraction, you just simply add one under 16. And it will make it 16/1

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Length width and height is 3 units
weqwewe [10]

Answer:

just three units no other numbers?

Step-by-step explanation:

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3 years ago
The domain of y = cot x is all real numbers such that _______.
Artyom0805 [142]

Answer:

Step-by-step explanation:

x≠ n*π, where n is an integer

because x/π can not be an integer

4 0
2 years ago
1. What is the value of the y variable in the solution to the following system of equations?
ollegr [7]

Part 1)

we have

3x-6y=3 ------> equation A

7x-5y=-11 ------> equation B

Multiply by -7 the equation A

-7(3x-6y)=-7*3

-21x+42y=-21 ------> equation C

Multiply by 3 the equation B

3*(7x-5y)=-11*3

21x-15y=-33 -------> equation D

Adds equation C and equation D

-21x+42y=-21 \\21x-15y=-33\\---------- \\ 42y-15y=-21-33\\27y=-54 \\ y=-2

therefore

<u>the answer Part 1) is the option A </u>

y=-2

Part 2)

we have

3x+y=6

y=-3x+6 ------> equation A

6x+2y=8

Simplify Divide by 2 both sides

3x+y=4

y=-3x+4 ------> equation B

the lines A and B are parallel lines, because the slope m is equal

so

The system has no solution

therefore

<u>the answer Part 2) is the option D</u>

There is no x value as there is no solution to the system.

Part 3)

we have

4x+2y=6 ------> equation A

x-y=3

y=x-3  ------> equation B

substitute equation B in equation A

4x+2[x-3]=6

6x-6=6

6x=12

x=2

therefore

<u>the answer part 3) is the option D</u>

x=2

Part 4)

Let

x---------> The number of one-step equations

y---------> The number of two-step equations

we know that

x+y=1,120

x=1,120-y -------> equation A

3x-2y=1,300 ------> equation B

substitute equation A in equation B

3[1,120-y]-2y=1,300

3,360-5y=1,300

5y=3,360-1,300

5y=2,060

y=412

therefore

<u>the answer part 4) is  the option D</u>

y=412

8 0
3 years ago
Read 2 more answers
Would You Rather? Snack Attack!
irga5000 [103]

Answer:

I would buy 8 bags of everyone's favorite snacks because it's cheaper and everyone gets what that want.

Step-by-step explanation:

This is just my opinion...Hope it helps

7 0
2 years ago
Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
3 years ago
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