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sergejj [24]
3 years ago
9

Let A and B be subsets of a universal set U and suppose n(U) = 400, n(A) = 115, n(B) = 90, and n(A ∩ B) = 50. Find the number of

elements in the set.
Mathematics
1 answer:
babunello [35]3 years ago
8 0

By the inclusion/exclusion principle,

n(A\cup B)=n(A)+n(B)-n(A\cap B)=155

There are 400 elements in the universal set U, which means there are 400 - 155 = 245 elements not accounted for by A\cup B, or

n(U)=n(A\cup B)+n((A\cup B)^C)\implies n((A\cup B)^C)=245

That's all you can really determine from the given info. Considering the language of the problem, "Find the number of elements in the set", I find it hard to believe that the set it's talking about isn't mentioned.

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3 years ago
9a-18b+21c apply distributive property to factor out gcf of all three terms
horsena [70]
The GCF of the three terms (9a, -18b and 21c) is 3

Rewrite each of the terms so 3 is a factor
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So we can say...
9a - 18b + 21c = 3*3a - 3*6b + 3*7c
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If you distribute outer 3 to each of the inner terms and multiply, you'll get the original expression again.

3 0
2 years ago
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Radda [10]

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For additional information:

The  period T of the function y=3sin(4t) is;

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The sine function with amplitude A = 0.75 and period T = 10, is

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Drawing the sine and cosine function on the same plot shows

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The cosine

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2 years ago
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saw5 [17]
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3 years ago
Consider the figure below.<br><br><br><br> Find the value of x.
Flauer [41]

Answer:

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