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sergejj [24]
3 years ago
9

Let A and B be subsets of a universal set U and suppose n(U) = 400, n(A) = 115, n(B) = 90, and n(A ∩ B) = 50. Find the number of

elements in the set.
Mathematics
1 answer:
babunello [35]3 years ago
8 0

By the inclusion/exclusion principle,

n(A\cup B)=n(A)+n(B)-n(A\cap B)=155

There are 400 elements in the universal set U, which means there are 400 - 155 = 245 elements not accounted for by A\cup B, or

n(U)=n(A\cup B)+n((A\cup B)^C)\implies n((A\cup B)^C)=245

That's all you can really determine from the given info. Considering the language of the problem, "Find the number of elements in the set", I find it hard to believe that the set it's talking about isn't mentioned.

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6 0
1 year ago
1. The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest
olga_2 [115]

Answer:

a)

$2.79 per pound.

$0.93 per apple.

b)

Unit price per pound is typically used because weight and size of every      apple is not same.

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5 pound bag of organic apples = $13.95

1 pound bag of organic apples = $13.95/5

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The unit price of apples that cost $13.95 for 5 pounds is $12.79 per pound.

<em>As a general rule, 1 pound of apples is equal to: 4 small apples. 3 medium apples. 2 large apples. So, here we assume that apples are of medium size.</em>

3 apples cost = $2.79

<em>The unit price means 'what is the cost of 1 apple'</em>

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The unit price of apples that cost $2.79 for 3apples is $0.93 per apple.

<em />

4 0
3 years ago
Read 2 more answers
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