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3 years ago

Can i get help plzz .....

Mathematics

1 answer:

wel3 years ago

3 0

Answer:

$0.30

Step-by-step explanation:

If you already spent $5 then you have $6 remaining so you will just divide 6 and 20 and you will get 0.3 so $0.30

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Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be

Rina8888 [55]

This is a combination problem.

Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.

The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.

This is the formula I used because the order is not important and repetition is not allowed.

Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.

numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960

Combination = 39,916,800 / 120,960 = 330

There are 330 ways that the instructor can choose 4 students for the first group

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If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

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