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IrinaK [193]
1 year ago
12

Pleeeaaseee helllppppp!!!!​

Mathematics
1 answer:
Phoenix [80]1 year ago
3 0

Answer:

sin\theta=\dfrac{1}{2}

=============

<h3>Given</h3>

  • cos \theta=\dfrac{\sqrt{3} }{2}

<h3>To find</h3>

  • The value of sin\theta

<h3>Solution</h3>

Use <u>identity</u> sin^2\theta+cos^2\theta=1 :

  • sin^2\theta=1-cos^2\theta
  • sin^2\theta=1-(\dfrac{\sqrt{3} }{2} )^2
  • sin^2\theta=1-\dfrac{{3} }{4}
  • sin^2\theta=\dfrac{{1} }{4}
  • sin\theta=\sqrt{\dfrac{{1} }{4} }
  • sin\theta={\dfrac{{1} }{2} }
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vodomira [7]
<h2>Steps:</h2>

So for this, we will be completing the square to solve for m. Firstly, subtract 8 on both sides:

2m^2-16m=-8

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m=4\pm 2\sqrt{3}

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