Question

Find the two straight lines represented by x² + 5xy - 6y² = 0​

Answer 1

By factorizing, we have

$x^2 + 5xy - 6y^2 = (x - y) (x + 6y) = 0$

so that

$x - y = 0 \implies \boxed{y = x}$

or

$x + 6y = 0 \implies \boxed{y = -\dfrac x6}$