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3 years ago

How Do I do proofs for proving triangles?

1 answer:

4 0

You must have been taught postulates and theorems that allow you to prove triangles congruent, such as SSS, SAS, ASA, etc. Look at the given information of a proof, and see how from the given information, using definitions, postulates, and theorems you have already learned, you can show pairs of corresponding sides and angles to be congruent that will fit into the above methods. Then use one of the methods to prove the triangles congruent.

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Please help me out here I'm failing math.

natulia [17]

Answer:

-4r - 11 = 4r + 21

-4r -4r = 21 + 11

-8 = 32 (Divide both sides by -8)

/ /

-8 -8

= -4

8 0

3 years ago

Help will mark Brainliest!!

BartSMP [9]

Answer:

-20.5

Step-by-step explanation:

Using a basic calculator, you divide 10.25 by -.5 which easily gives -20.5

5 0

2 years ago

Solve by using elimination. Express your answer as an Ordered pair (-x +2y=3 3x-2y=7

MAVERICK [17]

Answer:

(5,4)

Step-by-step explanation:

-x+2y=3

3x-2y=7

Add the like terms( 2y and -2y)(-x and 3x)(3 and 7) together. Do this vertically. 2y and -2y cancel eachother out.

2x=10

Divide both sides by 2

x=5

To find y, substitute x in for y in one of the equations

-5+2y=3

add 5 to both sides

2y=8

Divide both sides by 2

y=4

Check:

-5+2(4)=3
3=3

4 0

3 years ago

3/5 ÷ 1 1/4 = (20 points)

Anna11 [10]

3/5 ÷ 1 1/4 = 0.48

0.48 will be your anwer

7 0

3 years ago

Solve the quadratic. 4x^2+4-20=0 brainlist if you explain

frez [133]

Answer:

x = -1/2(1 +√21) ≈ -2.79129
x = -1/2(1 -√21) ≈ 1.79129

Step-by-step explanation:

We assume the middle term is supposed to be 4x.

We can remove a common factor of 4 to simplify this a bit.

x^2 +x -5 = 0

This is of the form

ax^2 +bx +c = 0

where a=1, b=1, c=-5.

The quadratic formula gives the solutions as ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Filling in the given coefficients, we have ...

x = (-1 ±√(1^2 -4·1·(-5)))/(2·1)

x = (-1±√21)/2

The solutions are x = -1/2(1 +√21) and -1/2(1 -√21).

_____

If what you wrote is what you intend, then the equation simplifies to 4x^2 -16 = 0.

Dividing by 4 and factoring the difference of squares gives ...

x^2 -4 = 0

(x -2)(x +2) = 0

These factors are zero (hence their product is 0) for the values x = 2 and x = -2.

The solutions are x=2 and x=-2.

5 0

3 years ago