If we have two similar triangles:
Triangle 1 (base 1 , height1).
Triangle 2 (base 2, height 2)
Then:
base 1 /height 1=base 2 /height 2
Data:
base 1=0.2 m
height 1= 1 m
base 2= 8 m
height 2=x
We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
x=8 m²/0.2 m
x=40 m
Answer. the heigth of the tower will 40 m
Answer:
mFG = 67r ( Where r is the radius of the circle)
∠ECF = 67°
Step-by-step explanation:
i) m FG
Join CG
∠GCF=67°
(As FG=ED and equal chords subtend equal angle at center)
Now The length of the minor arc is given by the formula
m arc FG =

∠C=67
m arc FG = 
m arc FG = 67r
Where r is the radius of the circle.
2. ∠ECF = 67°
It is because of the rule which says that equal chords subtend equal angle at center
DE = EF
Hence ∠DCE = ∠ECF
Answer:
5v^2x + 4
Step-by-step explanation:
I'm not sure but i hope this help's
Hi..... the domain(D) will be:

Thanks... :)