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11Alexandr11 [23.1K]
3 years ago
8

How many square feet of paper do you need to cover a cube with a side 10in long

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
10in = 0.833333ft^2 that is the total amount for one side. For a cube that has 6 sides, you multiply 0.833333 by 6.

You need <span>4.999998ft^2 of paper</span>
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The question is telling you that the length of the rectangle is 3 metres more than twice the width.

So let:

<em>w= width</em>

<em>L= length</em>

Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>


They also tell you the perimeter is 48 metres.

<em>P= L+L+w+w</em>

So the equation of the perimeter is:

<em>48= (2w+3)+(2w+3)+2w +2w</em>

<em>48= 2(2w+3) + 4w</em>


To find w, expand and simplify.

<em>48= 4w+6+4w</em>

<em>48= 8w + 6</em>

<em>42= 8w</em>

<em>5.25=w</em>


Now that you know the width, plug in the value into the length equation:

<em>L= 2w+3</em>

<em>L=2(5.25)+3</em>

<em>L=10.50+3</em>

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