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2 years ago

Find x and y.help please ty:)

Mathematics

1 answer:

Pavel [41]2 years ago

3 0

Please, make sure you understand the solution:

We can notice that x + (x - 28) = 90

2x - 28 = 90
2x = 118
x = 59

Now for y:

We can notice that y + 90 + x = 180

y + 90 + 59 = 180
y + 149 = 180
y = 180 - 149

y = 31

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Explain why the equation 5z + 2 = 5z has no solution.

suter [353]

$5z + 2 = 5z \\ 5z - 5z = - 2 \\ 0 = - 2$

Answer : This is because when 5z minus 5z, it is nullified, with no way to determine the value of z. 5z - 5z = 0
That is why there is no solution for this equation.

Hope this helps. - M

5 0

3 years ago

What is the solution set for 2x+5y>-1 and 4x-3<-3?

bekas [8.4K]

PROBLEM ONE

•

Solving for x in 2x + 5y > -1.

•

Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

$\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}$

$\displaystyle\ x > \frac{-1 - 5y}{2}$

So, the solution for x in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 - 5y}{2}$

•

Solving for y in 2x + 5y > -1.

•

Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

$\displaystyle\frac{5x}{5} > \frac{-1 -1x}{5}$

$\displaystyle\ x > \frac{-1 -1x}{5}$

So, the solution for y in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 -1x}{5}$

•

PROBLEM TWO

•

Solving for x in 4x - 3 < -3.

•

Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

$\displaystyle\frac{4x}{4}$

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

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- Marlon Nunez

7 0

3 years ago

The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant

Kipish [7]

The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant IV

Hope it helps

7 0

3 years ago

Read 2 more answers

Solve for x. 79 (8x - 4) 3 -(3x + 17)

Liono4ka [1.6K]

Answer:

-2.4

Step-by-step explanation:

maybe... i am 99.99% sure

6 0

2 years ago

During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were record

SpyIntel [72]

Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Part 2:

H0:

Ha:

Part 3: The test statistic is given as 3.0081.

Part 4: The p-value is given as 0.39037

Step-by-step explanation:

As per the data

Part 2

H0:

Ha:

Part 3

As per the sample is of 300 homes, the expected values are given as

ABC=p(ABC)*300=0.30*300=90

CBS=p(CBS)*300=0.27*300=81

NBC=p(NBC)*300=0.26*300=78

IND=p(IND)*300=0.17*300=51

Now the values actually are given as

ABC=94

CBS=71

NBC=88

IND=47

So the test static is given as

So the test statistic is given as 3.0081.

Part 4

Now the degree of freedoms are given as 4-1=3

and chi square is given as 3.0081 so for α = 0.05 , the p-value is given as 0.39037

Part 1.

As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

4 0

3 years ago

Find x and y.help please ty:)​

Find x and y.help please ty:)