<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2
Um I think it's like because there's a zero difference like ten thousands have more zeros
Line perpendicular to a given line is = 1/m
To find m, use m =y2-y1/x2-x1 formula
m = (8-(-3))/(-7-4)
m = 11/-11,
m = -1
Use y= mx+c to find equation of line
Plug in a pair of values,
-3= -1(4)+ c
c= 1
Thus, equation is:
y = -x+1
Equation of line perpendicular to this line is:
y= x+1
Hope it helps :)
Pls mark it as Brainliest :)
Answer:Geometric mean: 56
Step-by-step explanation:
Calculation:
Statistical file:
{64, 49}
Geometric mean: 56
slope = (6 - 1)/(-2 - 1) = 5/-3 = -5/3
Equation
y - 6 = -5/3 (x + 2)
Hope it helps