Question

How do I do the distribution table and the proccess plss help

Answer 1

Answer + Step-by-step explanation:

p(X=3) = the probability that X is equal to 1 or 2 or 3 minus (the probability that X is equal to 2 plus the probability that X is equal to 1)

Because ,when X = 2 or X = 1  the largest number is not 3 so we have to subtract those values .

……………………………………………………………

the probability that X is equal to 1 or 2 or 3 is :

$(\frac{3}{6} )^4 = \frac{81}{1296}$

Then

$p\left( X=3\right) =\frac{81}{1296} -(\frac{1}{1296} +\frac{15}{1296}) =\frac{65}{1296}\\\\p\left( X=4\right) =\frac{4^4}{1296} -(\frac{1}{1296} +\frac{15}{1296}+\frac{65}{1296}) =\frac{175}{1296}\\\\p\left( X=5\right) =\frac{5^4}{1296} -(\frac{1}{1296} +\frac{15}{1296}+\frac{65}{1296}+\frac{175}{1296}) =\frac{369}{1296}$

Verification:

1+15+65+175+369+671 = 1 296