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GalinKa [24]
2 years ago
13

What is the answer for number 10

Mathematics
1 answer:
balandron [24]2 years ago
6 0

Answer:

b

Step-by-step explanation:

b just honestly looks right and its my lucky letter so yaa...

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In the triangle below,
Greeley [361]

Answer:

12.3

Step-by-step explanation:

You will use cosine to solve for y because you are given the hypontenuse and need to find the adjacent side.

cos 35 degrees = adjacent/hypontenuse

cos 35 = y/ 15

15( cos35 ) = y

y=12.287

=12.3

7 0
3 years ago
Determine the value of K that would make this expression a perfect square
Mumz [18]

Answer: k=9/4

Step-by-step explanation: We can do this by finding a number that adds up to 3 when multiplied by 2. The best way to do this is to use ((b^2)/4) which can usually find you the number for a perfect square based on b, which we have. So, 3^2 / 4 =9/4, meaning k=9/4. We can check:

>x^2 +3x +9/4

> (x+3/2)(x+3/2)

Perfect square.

4 0
3 years ago
Can you help me?<br>Answer the question please​
Harlamova29_29 [7]

Hey there! :D

1. c - 7 = 32

To solve this problem, add the difference and the subtrahend of the given equation.

32 + 7 = \boxed{\sf 39}

Checking:

To check, simply substitute the conclusion on the unknown quantity.

39 (c) - 7 = 32

Thus, the equation was correct which gives us the answer that:

\large \boxed{ \sf {\: c = 39}}

\begin{gathered} \\ \end{gathered}

2. r + 4 = 39

To solve this problem, subtract the sum and the addend of the given equation.

39 - 4 = \boxed{\sf 35}

Checking:

To check, simply substitute the conclusion on the unknown quantity.

35 (r) + 4 = 39

Thus, the equation was correct which gives us the answer that:

\large\boxed{ \sf {r \: = \: 35}}

5 0
2 years ago
The altitude to the hypotenuse of a right triangle divides the hypotenuse into segments 9 in. and 12 in. long. What's the length
kow [346]
The length of he altitude to the hypotenuse is the square root of 108
3 0
3 years ago
Please please help i beg ill give brainlist
Marta_Voda [28]

Answer:

a_{15}=-268,435,456

Step-by-step explanation:

First, find what factor each term is multiplied by to get to the next. To do this, divide the second term by the first, the third term by the second, etc

4\div-1=-4\\-16\div4=-4\\64\div-16=-4

The common factor is 4. Using that, you can now write the equation for the geometric sequence in the form of:

a_n=a_1x^{n-1}

It looks scarier than it is. aₙ is the nth term in the sequence, x is the factor, and n is the index in the sequence, that's all it is.

Plug in the information we have to get the equation for this sequence:

a_n=(-1)(-4)^{n-1}

Then, you can solve for the 15th term:

a_{15}=(-1)(-4)^{15-1}\\a_{15}=(-1)(-4)^{14}\\a_{15}=(-1)(268,435,456)\\a_{15}=-268,435,456

Basically, just raise the scale factor to the power of the term you want minus 1, then multiply that by the first number.

4 0
2 years ago
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