We have been given that Alexis received an 85, 89, and 92 on three tests and we are asked to find out the minimum grade Alexis can score on the fourth test in order to have an average of at least 90.
Let x be marks Alexis can score on the fourth test.
Since we know average is sum of all the numbers divided by number of items. Now we can set our given information in the average formula to get the minimum numbers Alexis can score on the fourth test.
Therefore, the minimum grade Alexis can score on the fourth test is 94, in order to have an average of at least 90.
Answer:
HI ≈ 12.22
Step-by-step explanation:
tan I = GH / HI
tan 42° = 11 / HI = 0.90
HI = 11/0.90 = 12.22
Well... in the first one you have a probability of 72 percent. In the secondd box you have a probability of 34 percent.
Simplifying
h(t) = -1t2 + -2t + 30
Multiply h * t
ht = -1t2 + -2t + 30
Reorder the terms:
ht = 30 + -2t + -1t2
Solving
ht = 30 + -2t + -1t2
Solving for variable 'h'.
Move all terms containing h to the left, all other terms to the right.
Divide each side by 't'.
h = 30t-1 + -2 + -1t
Simplifying
h = 30t-1 + -2 + -1t
Reorder the terms:
h = -2 + 30t-1 + -1t
Answer:
<em>Predicted height: 57.42 inches</em>
<em>Residual: 2.58 inches</em>
Step-by-step explanation:
<u>Regression Equation</u>
The regression equation for the height of the children (Hgt) and their age (Age) is given by the expression
Hgt = 24.3 + 2.76(Age)
We must compare the predicted value of the equation vs the real data point Age=12, Height=60
Computing the predicted height
Hgt = 24.3 + 2.76(12)
Hgt=57.42 inches
The residual is the difference between the real data point and the predicted value
R=60-57.42
R=2.58 inches