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3 years ago

Kathy can clean 12 house in 10 hrs. If she goes at a steady pace. How many hrs. will it take her to clean 27 houses?

2 answers:

6 0

To solve this, set up a proportion with X being our unknown. If she cleans 12 houses in 10 hours, she cleans 27 houses in X hours. It will look like $\frac{12}{10} = \frac{27}{x}$ .

Now cross-multiply to get 12x = 27(10) or 12x = 270. Divide by 12 on both sides to isolate x, X = 22.5.

It will take Kathy 22.5 hours to clean 27 houses. Must be some pretty small houses.

FromTheMoon [43]3 years ago

6 0

12 houses/10 hours=1.2 house per hour
27 houses/1.2 houses per hour=22.5 hours

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3 years ago

India is the second most populous country in the world, with a population of over 1 billion people. Although the government has

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a) $P(X$

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c) $P(2 \leq X \leq 5)=P(x=2) +P(X=3) +P(X=4)+P(X=5)=0.12+0.18+0.24+0.13=0.67$

Step-by-step explanation:

For this case we have the following probability distribution function:

X P(X)

1 0.04

2 0.12

3 0.18

4 0.24

5 0.13

6 0.15

7 0.10

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Total 1.00

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For this case we want this probability:

$P(X$

Part b

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For this case we want this probability:

$P(X \geq 5)=P(X=5) +P(X=6) +P(X=7) +P(X=8)= 0.13+0.15+0.10+0.04=0.42$

Part c

What is the probability that the number of members in a typical household in India is strictly between 2 and 5? (Round your answer to 2 decimal places.)

We want this probability:

$P(2 \leq X \leq 5)=P(x=2) +P(X=3) +P(X=4)+P(X=5)=0.12+0.18+0.24+0.13=0.67$

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3 years ago

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(D)Equilateral Triangle

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Given a circle centre M; and

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