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2 years ago

FAST!

Mathematics

2 answers:

sesenic [268]2 years ago

3 0

Ggggggghhggggggggggg

Marysya12 [62]2 years ago

3 0

Answer:

69 there hope it helps ;)

Step-by-step explanation:

420

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Jason bought a car for $12500. According to the insurance company, the value of the car depreciates by 7% each year. What will t

Orlov [11]

Answer:

8696.10

Step-by-step explanation:

If a car depreciates by 7% each year, this means that 7% of its value that year is subtracted from its previous value. In other words, you can multiply its value by (1-0.07)=0.93.

$12500\cdot 0.93^5\approx 8696.10$ . Hope this helps!

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3 years ago

Irene wants to list the factors for 88. She

Paladinen [302]

Almost; she's just missing 1, since 1*88 = 88.

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2 years ago

An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou

Katyanochek1 [597]

Answer:

$t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17$

$p_v =P(t_{(5)}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation

The mean and sample deviation can be calculated from the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}$

$\bar X=29.35$ represent the sample mean

$s=1.365$ represent the sample standard deviation

$n=6$ sample size

$\mu_o =30$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :

Null hypothesis: $\mu \geq 30$

Alternative hypothesis: $\mu < 30$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=6-1=5$

Since is a one-side left tailed test the p value would given by:

$p_v =P(t_{(5)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

5 0

2 years ago

Evaluate and answer in standard form:<br><br>4^2/3^2

Semenov [28]

the answer is : 1.7777

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3 years ago

What is the measure of angle a. round your answer to the nearest hundredth

joja [24]

Answer:use a right triangle calc. On the web it does it for you and shows you how it got the answer.

Step-by-step explanation:

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2 years ago