2 years ago

FAST!

Mathematics

2 answers:

sesenic [268]2 years ago

3 0

Ggggggghhggggggggggg

Marysya12 [62]2 years ago

3 0

Answer:

69 there hope it helps ;)

Step-by-step explanation:

420

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Find the zeroes of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30.

katen-ka-za [31]

Step-by-step explanation:

x⁴ − 5x³ + 11x² − 25x + 30

x⁴ − 5x³ + 6x² + 5x² − 25x + 30

x² (x² − 5x + 6) + 5 (x² − 5x + 6)

(x² + 5) (x² − 5x + 6)

(x² + 5) (x − 2) (x −3)

The zeros are 2, 3, and ±√5i.

7 0

3 years ago

Factor completely

ZanzabumX [31]

Use the (-b + - sqrt( b^2 - 4ac) ) /2a Formula.
a = 1 b= 10 c= 24
so you get .. (x+6 )(x+4) A

4 0

3 years ago

Simplify the expression.

Nana76 [90]

The answer is the A. I hope this helps!

6 0

3 years ago

I need help asap I don't get this

musickatia [10]

The correct answer is C. They are going down by 3.

4 0

3 years ago

What values of b satisfy 3(2b + 3)2 = 36?

KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36

we have

$3(2b+3)^2 = 36$

Divide both sides by $3$

$(2b+3)^2 = 12$

take the square root of both sides

$( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3$

$b1=\frac{\sqrt{12}}{2} -\frac{3}{2}$

$b1=\sqrt{3} -\frac{3}{2}$

$b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}$

$b2=-\sqrt{3} -\frac{3}{2}$

therefore

the answer is

the values of b are

$b1=\sqrt{3} -\frac{3}{2}$

$b2=-\sqrt{3} -\frac{3}{2}$

6 0

2 years ago

Read 2 more answers