<img src="https://tex.z-dn.net/?f=%287%20-%208%29%20%5Ctimes%202%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(7

Hunter-Best [27]

3 years ago

{}^{2} " alt="(7 - 8) \times 2 {}^{2} " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

forsale [732]3 years ago

8 0

The guy above is correct

Diano4ka-milaya [45]3 years ago

7 0

Answer: -4
Work: 7-8 = -1 x 4

You might be interested in

Find the function of ğ...<br>does anybody knows?

Basile [38]

If we let g(x) = x + 2, then
${(x + 2)}^{2} + 2 = ( {x}^{2} + 4x + 4) + 2 \\ = {x}^{2} + 4x + 6$
Of course if we let f(x) = x + 2, then

7 0

3 years ago

The area of the regular octagon is approximately 54 cm2. What is the length of line segment AB, rounded to the nearest tenth?

erastova [34]

Answer:

AB = 3.3 cm

Step-by-step explanation:

The formula to find out area of a regular octagon is given by

$A=2(1+\sqrt{2})a^{2}$

where a is the length of each side of the regular octagon.

Plugin A=54 into the formula

$54=2(1+\sqrt{2})a^{2}$

Divide both sides by 2

$\frac{54}{2} =\frac{2}{2} (1+\sqrt{2})a^{2}$

$27 = (1+\sqrt{2})a^{2}$

Plugin √2 as 1.41

$27 = (1+1.41)a^{2}$

$27 = (2.41)a^{2}$

Divide both sides by 2.41

$\frac{27}{2.41} = \frac{2.41}{2.41} a^{2}$

$11.20 = a^{2}$

Taking square root on both sides

$\sqrt{11.20} = \sqrt{a^{2}}$

a = 3.346

a = 3.3 cm (rounded to nearest tenth)

so, length of side AB = 3.3 cm

6 0

3 years ago

Read 2 more answers

Help, please <br><br> 22=4x+6

skad [1K]

Minus 6 from both sides, 4x = 16, divide by 4, x = 4

4 0

4 years ago

Read 2 more answers

Find the tenth term in each sequence 32, 42, 50, 58, 66

kotykmax [81]

Answer:

106

Step-by-step explanation:

The pattern is +8. 66 is the last number given which is the 5th number. So we need to have five numbers. we can do 8*5=40 and add 40 to 66. Your answer is 106.

8 0

3 years ago

1.) Using appropriate properties find. -2/3×3/5+5/2-3/5×1/6

frez [133]

Answer:

Step-by-step explanation:

Multiply then add

4 0

3 years ago