Question

The expressionx^2-9/x2+6x+8 is equal to zero when x = .

Answer 1

Hello !

Answer:

When x = -3 or x = 3

Step-by-step explanation:

$\frac{ {x}^{2} - 9}{ {x}^{2} + 6x + 8} = 0$

$\Leftrightarrow \frac{ {x}^{2} - 9 }{ {x}^{2} + 6x + 8} \times ( {x}^{2} + 6x + 8) = 0 \times ( {x}^{2} + 6x + 8)$

$\Leftrightarrow {x}^{2} - 9 = 0$

$\Leftrightarrow(x - 3)(x + 3) = 0$

$\Leftrightarrow \: x - 3= 0 \: or \: x + 3 = 0$

$\Leftrightarrow \: x = 3 \: or \: x = - 3$

$\boxed{S = {-3 \: \: or \: \: 3}}$