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Tcecarenko [31]
2 years ago
5

For a biology experiment, students labeled the plants in a greenhouse in order to track their heights over the next few weeks. T

he greenhouse contained ROSES labeled 1, 2, 3, 4, 5, 6, LILIES labeled 1, 2, 3, 4, 5, and VIOLETS labeled 1, 2, 3, 4. If a single flower is picked at random, what is the probability that the flower is NOT A ROSE?​
Mathematics
1 answer:
Eva8 [605]2 years ago
4 0

Using it's concept, it is found that there is a 0.6 = 60% probability that the flower is NOT A ROSE.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 6 + 5 + 4 = 15 flowers, out of which 5 + 4 = 9 are not roses, hence the probability is given by:

p = 9/15 = 0.6 = 60%.

0.6 = 60% probability that the flower is NOT A ROSE.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

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Use long division to find the quotient below.
Pachacha [2.7K]

Answer:

Number B: 4x+1

Step-by-step explanation:

I used synthetic division instead, But hope this helps.

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2 years ago
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NEED HELP PLZ
Angelina_Jolie [31]

Answer:

0.14

Step-by-step explanation:

From the question given above, the following data were obtained:

Grade A = 5

Grade B = 10

Grade C = 15

Grade D = 3

Grade F = 2

Sample space (S) = 35

Probability of getting grade A, P(A) =?

The probability that a student obtained a grade of A can be obtained as follow:

Probability of getting grade A, P(A) =

Event of A (nA) / Sample space, (nS)

P(A) = nA/nS

P(A) = 5/35

P(A) = 0.14

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6 0
2 years ago
How do you do question b?
notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\

-----------------

This means,

\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\

is the solution with the initial condition y(0) = 0.

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2 years ago
Consider the following equation, bh+hr=25 when solving for r
Komok [63]
Solve for r.

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Subtract bh from both sides.

hr = 25 - bh

Divide h on both sides.

r = 25 - bh / h

The two h's cancel each other out.

r = 25 - b

Hope this helps!
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3 years ago
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Gre4nikov [31]
1 yard = 3 feet, so we would do 3×84, which is 252.

There are 252 feet in 84 yards.
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3 years ago
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