For a biology experiment, students labeled the plants in a greenhouse in order to track their heights over the next few weeks. T he greenhouse contained ROSES labeled 1, 2, 3, 4, 5, 6, LILIES labeled 1, 2, 3, 4, 5, and VIOLETS labeled 1, 2, 3, 4. If a single flower is picked at random, what is the probability that the flower is NOT A ROSE?
1 answer:
Using it's concept, it is found that there is a 0.6 = 60% probability that the flower is NOT A ROSE.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 6 + 5 + 4 = 15 flowers , out of which 5 + 4 = 9 are not roses , hence the probability is given by:
p = 9/15 = 0.6 = 60%.
0.6 = 60% probability that the flower is NOT A ROSE.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
See below
Step-by-step explanation:
The function oscillates between -1 and 1, so the range is .
Answer for the question is A
Hello, 1.8444444....=1.8+1/10*0.44444.... =1.8+1/10*4/9 =1.8+4/90 =162/90+4/90 =166/90 =83/45 2.126262626...=2.1+1/10*0.262626... =2.1+1/10*26/99 =2.1+26/990 =2079/990+26/990 =2105/990 =421/198
(3 + 2i) - (5 - 7i)
Distribute the - sign
3 + 2i - 5 + 7i
Combine like terms
-2 + 9i
<span>(12.67 + 19.2)(3.99) / (1.36 + 11.366) = 31.87(3.99) / 12.726 = 127.1613 / 12.726 = 9.992</span>