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Rufina [12.5K]
4 years ago
11

He first term of a sequence is 2, and each subsequent term is the reciprocal of the square of the preceding term. what is the po

sitive square root of the fifth term?
Mathematics
1 answer:
polet [3.4K]4 years ago
4 0
The first term is a₁ = 2.
Each subsequent term is the reciprocal of the square of the preceding term.

2nd term:
a₂ = 1/2² = 1/4

3rd term:
a₃ = 1/(1/4)² = 1/(1/16) = 16

4th term:
a₄ = 1/16² = 1/256

5th term:
a₅ = 1/(1/256)² = 1/(1/65536) = 65536
The positive square root of the fifth term is
√(65536) = 256

Answer: 256
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Answer:

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Solution:

\ A = \ 3B - 18 \\\\ \ put \ the \ value \ of \ A \ in \ equation.....(i) \\\\  \ Equation:  \\ \\\Rightarrow  \ A\ +\ B \ =\ 90 \\\\\Rightarrow \ 3B\ -\  18 \ + \ B \ = \ 90 \\\\\Rightarrow \ 4B \ = \ 90 +18 \\\\\Rightarrow \ 4B = 108 \\\\ \Rightarrow  B = \frac{108}{4} \\\\ \Rightarrow   B \ = \ 27\\

\ put \ the \ value \ of \ B \ in \ equation (i).\\\\ \ Equation: \\\\\Rightarrow A+B=90\\\\\Rightarrow A+27=90\\\\\Rightarrow A=90-27\\\\\Rightarrow A= 63

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3 years ago
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