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Marina CMI [18]
2 years ago
8

Can someone help with this?

Mathematics
1 answer:
uysha [10]2 years ago
5 0

Answer:

146

Step-by-step explanation:

substitute x = 2, y = 3 into the expression

4(2)³ + 2(2)(3) - 2(3) + 3(2)²(3)²

= 4(8) + 12 - 6 + 3(4)(9)

= 32 + 12 - 6 + 108

= 38 + 108

= 146

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Evaluate the following integral (Calculus 2) Please provide step by step explanation!
Step2247 [10]

Answer:

\displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x=-\dfrac{2}{x+1}+\text{C}

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

<u>Given integral</u>:

\displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x

Factor the denominator:

\begin{aligned}\implies x^2+2x+1 & = x^2+x+x+1\\& = x(x+1)+1(x+1)\\& =  (x+1)(x+1)\\& =  (x+1)^2\end{aligned}

\implies \displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x=\int \dfrac{2}{(x+1)^2}\:\:\text{d}x

\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}

\implies \displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x=\int 2(x+1)^{-2}\:\:\text{d}x

\boxed{\begin{minipage}{4 cm}\underline{Integrating $ax^n$}\\\\$\displaystyle \int ax^n\:\text{d}x=\dfrac{ax^{n+1}}{n+1}+\text{C}$\end{minipage}}

Use <u>Integration by Substitution</u>:

\textsf{Let }u=(x+1) \implies \dfrac{\text{d}u}{\text{d}x}=1 \implies \text{d}x=\text{d}u}

Therefore:

\begin{aligned}\displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x & = \int 2(x+1)^{-2}\:\:\text{d}x\\\\& = \int 2u^{-2}\:\:\text{d}u\\\\& = \dfrac{2}{-1}u^{-2+1}+\text{C}\\\\& = -2u^{-1}+\text{C}\\\\& = -\dfrac{2}{u}+\text{C}\\\\& = -\dfrac{2}{x+1}+\text{C}\end{aligned}

Learn more about integration here:

brainly.com/question/27988986

brainly.com/question/27805589

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2 years ago
True or false: 3^-1 x 3^-1=3^1
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Answer:

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Step-by-step explanation:

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