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allochka39001 [22]
3 years ago
5

A.) y= 5x + 4 B.) y= -x + 8 C.) y= x - 10 D.) y= -4x + 3

Mathematics
2 answers:
creativ13 [48]3 years ago
3 0
Option B is your answer. 

If you plug it in, you get:

1 = -(7) + 8
1 = - 7 + 8
1 = 1, a true statement. 
Soloha48 [4]3 years ago
3 0
Try the x and y values in the equations and see which works.
  A.) 1 = 5*7 +4 . . . . nope
  B.) 1 = -7 +8 . . . . . true
  C.) 1 = 7 -10 . . . . . nope
  D.) 1 = -4*7 +3 . . . nope

The appropriate choice is ...
  B.) y = -x +8
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podryga [215]

Answer:

Matrix transformation = \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right].

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-5\\-2\end{array}\right]= (5,-2)

Q'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-6\\-3\end{array}\right]= (6,-3)

R'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-2\\-3\end{array}\right]= (2,-3)

3 0
3 years ago
What’s the 16th term?
kramer

Put 16 where n is, then do the arithmetic.

... a(16) = -6 + 3(16 -1)

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8 0
3 years ago
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Travka [436]

Answer:

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Step-by-step explanation:

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Romashka [77]

Answer:

The amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

Step-by-step explanation:

The given function is

f(t)=-\frac{1}{2}\sin (3t-2\pi)      .... (1)

The general form of sine function is

F(t)=A\sin (Bt-C)+D                 ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

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Therefore amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

8 0
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