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STALIN [3.7K]
2 years ago
6

A girl travels from garage a for 59km ti garage b on a bearing of 037degree and then turn right through 90degree and travels for

119km to garage c what is the bearing frim c from a if ac is 138km
Mathematics
1 answer:
Brums [2.3K]2 years ago
4 0

The bearing from C to A of the given travel path is gotten as; 100.63°

<h3>How to calculate the bearing?</h3>

From the bearing image attached, we can use trigonometric ratios to get;

tanx = opp/adj

x = 53 + θ ---------- eqn(1)

opp = 119

adj = 59

Thus;

tan x = 119/59

tan x = 2.0169

x = tan⁻¹(2.0169)

x = 63.63°

From eqn (1), we have;

θ = x - 53

θ = 63.63 - 53

θ = 10.63°

Thus, the bearing from C to A = 90 + 10.63 = 100.63°

Read more about Bearing at; brainly.com/question/22719608

#SPJ1

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