A girl travels from garage a for 59km ti garage b on a bearing of 037degree and then turn right through 90degree and travels for
1 answer:
The bearing from C to A of the given travel path is gotten as; 100.63°
<h3>How to calculate the bearing?</h3>From the bearing image attached, we can use trigonometric ratios to get;
tanx = opp/adj
x = 53 + θ ---------- eqn(1)
opp = 119
adj = 59
Thus;
tan x = 119/59
tan x = 2.0169
x = tan⁻¹(2.0169)
x = 63.63°
From eqn (1), we have;
θ = x - 53
θ = 63.63 - 53
θ = 10.63°
Thus, the bearing from C to A = 90 + 10.63 = 100.63°
Read more about Bearing at; brainly.com/question/22719608
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Answer:
Step-by-step explanation:
You need to analize the information provided in the exercise.
Observe the given figure.
You know that the line AC and and the line BD are parallel and they are cut by a transversal.
By definition, the pair of angles created by this intersection and are located inside the parallel lines and on opposite sides of the transversal, are called "Alternate Interior Angles".
Alternate Interior Angles are congruent, which means that they have equal measure.
Knowing this, you can identify that the angle "p" and the angle "n" are Alternate Interior Angles, therefore: