1. In ABC, m
Which expression correctly relates the lengths of the
sides of this triangle?
(1) ABC BC< CA
(3)
AC< BC < AB
(2) ABC AC< BC
(4) BC< AC < AB
1 answer:
Answer:
4 d
Step-by-step explanation:
Given D is mid-point of BC and AD⊥AC
From right angle △DAC
cosC=
a/2
b
=
a
2b
...(i)
also from cosine formulae
cosC=
2ab
a
2
+b
2
−c
2
...(ii)
From (i) and (ii) we get
a
2b
=
2ab
a
2
+b
2
−c
2
⇒4b
2
=a
2
+b
2
−c
2
⇒b
2
=
3
a
2
−c
2
∴cosAcosC=
2bc
b
2
+c
2
−a
2
.
a
2b
=
ca
[(
3
a
2
−c
2
)+c
2
−a
2
]
=
3
2
(
ca
c
2
−a
2
)
You might be interested in
it would be 9.93300
so 3 decimal places because the zeros don't count
x/20 = 21/14 (similar proportions)
x/20 = 3/2 (simplify by canceling out a factor of 7)
x = 30
12 because if u had 3 groups of 4 that would be 3+3+3+3